개발/개발 자료
(C#) XML파싱
시원한물냉
2015. 1. 22. 15:31
using System.Xml;
private HttpGet req = new HttpGet();
string url = "xml 형태의 주소";
req.Request(url);
XmlReader reader = XmlReader.Create(new StringReader(req.ResponseBody));
try{
reader.ReadToFollowing("NAME");
string xValue = reader.ReadElementContentAsString();
Console.WriteLine(xValue);
} catch (Exception){
Console.WriteLine("Exception");
}
reader.Close();